ANSWERS
A1) I'll check your graph
A2) I'll check your graph
B1) You should have a sketch
C1) B=20.2 x=32.8
C2) B=4.8 C=7
C3) A=61.9 x=39.1
C4) A=6.1 C=50.4
D3) 6.7sin(63)=x x=5.97 meters
D4)11.6tan(36.8)=x x=8.68 meters
D5) sin(x)=(6.5)/(6.7) x=75.97 degrees
D6) tan(x)=533/1100 x=25.85 degrees
D11) 300sin(69)=x x=280.07 meters
300cos(69)=y y=107.51 meters
D Created) ex. Q. Suppose a basketball players makes a bounce pass from his waist 3 feet above the ground. If he wants it to bounce 4 feet from his feet, at what angle from his body should he release the ball from? A. 53.13 degrees
A2) I'll check your graph
B1) You should have a sketch
C1) B=20.2 x=32.8
C2) B=4.8 C=7
C3) A=61.9 x=39.1
C4) A=6.1 C=50.4
D3) 6.7sin(63)=x x=5.97 meters
D4)11.6tan(36.8)=x x=8.68 meters
D5) sin(x)=(6.5)/(6.7) x=75.97 degrees
D6) tan(x)=533/1100 x=25.85 degrees
D11) 300sin(69)=x x=280.07 meters
300cos(69)=y y=107.51 meters
D Created) ex. Q. Suppose a basketball players makes a bounce pass from his waist 3 feet above the ground. If he wants it to bounce 4 feet from his feet, at what angle from his body should he release the ball from? A. 53.13 degrees
ANSWERS
F Created) ex. (2/√2)sin(x) = 1 x=pi/4
2cos(3x) = 1 x=pi/9
-(√3)+tan(x/4) = 0 x=4pi/3
H1) D
H3) C
H5) A
H6) B
H7) C
H8) C
H9) C
H10) A
H12) B
H13) A
H14) A
H15) D
2cos(3x) = 1 x=pi/9
-(√3)+tan(x/4) = 0 x=4pi/3
H1) D
H3) C
H5) A
H6) B
H7) C
H8) C
H9) C
H10) A
H12) B
H13) A
H14) A
H15) D